Question 197850
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If the roots of a quadratic equation are *[tex \LARGE a] and *[tex \LARGE b], then the factors of the quadratic polynomial must be:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (x - a)(x - b)], therefore:


You have:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x - \frac{2}{3} = 0] and


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x - (-\frac{4}{5}) = 0] so you can say:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (3x - 2)(5x + 4) = 0]


Expand the binomials using FOIL and you have it.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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