Question 27317
Multiplicative inverse means that when you multiply it by the number you'll get one, so what you're essentially doing is solving for is x in this equation:
{{{(4-2i)x=1}}}
{{{x=1/(4-2i)}}}
However you can't leave an i value in the bottom of the equation, so you have to multiply the top & bottom by 4+2i.
{{{x=(1/(4-2i))*((4+2i)/(4+2i))}}}
{{{x=(4+2i)/(16-4i^2)}}}Since {{{i^2=-1}}}:
{{{x=(4+2i)/(20)}}}

In other words, dividing by (4-2i) is the same thing as multiplying by (4+2i)/20.