Question 197740
Remember  y=mx+b,,,,and  perpendicular  lines  have  slopes  that  are  negative  reciprocals
.
y= ( -2/3 ) x  +7
.
slope  is  -2/3,,,,,slope  in  perpendicular  line  is  ( +3/2)
.
y= 3/2 x  +b
.
at  ( 4,-1)
.
(-1) = 3/2 (4) +b
.
-1 -6 = b
.
-7 = b
.
Inserting  in  y=mx+b,,,,,y= 3/2 x -7
.
checking
substitute  ( 4, -1)  into  y = 3/2 x -7
-1 = (3/2)(4) -7 = -1 ,,,,ok