Question 197712
{{{(t^4)/(t^8)=t^(4-8)=t^(-4)}}}



So {{{(t^4)/(t^8)=t^(-4)}}}



Since we want {{{t^(-4)}}} to be of the form {{{At^B}}}, this means that {{{t^(-4)=At^B}}}. So this must mean that {{{A=1}}} and {{{B=-4}}}