Question 197700


Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(3,6\right)] and *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(1,-4\right)].



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(-4-6)/(1-3)}}} Plug in {{{y[2]=-4}}}, {{{y[1]=6}}}, {{{x[2]=1}}}, and {{{x[1]=3}}}



{{{m=(-10)/(1-3)}}} Subtract {{{6}}} from {{{-4}}} to get {{{-10}}}



{{{m=(-10)/(-2)}}} Subtract {{{3}}} from {{{1}}} to get {{{-2}}}



{{{m=5}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(3,6\right)] and *[Tex \LARGE \left(1,-4\right)] is {{{m=5}}}