Question 197701


Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(-4,2\right)] and *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(2,2\right)].



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(2-2)/(2--4)}}} Plug in {{{y[2]=2}}}, {{{y[1]=2}}}, {{{x[2]=2}}}, and {{{x[1]=-4}}}



{{{m=(0)/(2--4)}}} Subtract {{{2}}} from {{{2}}} to get {{{0}}}



{{{m=(0)/(6)}}} Subtract {{{-4}}} from {{{2}}} to get {{{6}}}



{{{m=0}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(-4,2\right)] and *[Tex \LARGE \left(2,2\right)] is {{{m=0}}}