Question 197358
In 1994, the life expectancy of males in a certain country was 69.6 years.
 In 1998, it was 73.0 years. Let E represent the life expectancy in year t
 and let t represent the number of years since 1994.
:
Find the slope
In 1994; x1=0 and y1=69.6
In 1998; x2=4 and y2=73
:
Find the slope (m) using the slope equation: m = {{{(y2-y1)/(x2-x1)}}}
m = {{{(73-69.6)/(4 - 0))}}} = {{{(3.4)/(4)}}} = .85
:
Use the point/slope formula to write the equation; y - y1 = m(x - x1)
y - 69.6 = .85(x - 0)
y = .85x + 69.6
:
therefore:
The Linear function E(t) that fits the data is.
E(t)= .85t + 69.6
:
Use the Function to predict the life expectancy of males in 2008.
This means t=14; substitute 14 for t in the equation
E(14)= .85(14) + 69.6
E(14)= 11.9 + 69.6
E(14)= 81.5 yrs is the life expectancy in 2008