Question 197568
    what is the area of an equilateral triangle with side lengths of 3?
.
Area of triangle = (1/2)bh
where
h is height
b is base (3)
.
Calculate height using Pythagorean theorem:
Let h = height
h^2 + (3/2)^2 = 3^2
h^2 + (9/4) = 9
h^2 = 9 - 9/4
h^2 = 36/4 - 9/4
h^2 = 27/4
h = {{{ 3/2 * sqrt(3)}}}
.
Plugging it all back into:
Area of triangle = (1/2)bh
Area of triangle = {{{(1/2)(3)(3/2 * sqrt(3))}}}
Area of triangle = {{{(9/4)(sqrt(3))}}}