Question 197543
The perimeter of a rectangle is 262 inches. The length exceeds the width by 63 inches. Find the length and the width.
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P = 2L + 2W = 262
L = W + 63
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262 = 2(W + 63) + 2W
4W + 126 = 262
4W = 136
W = 34
L = 97