Question 197499
Start with the formula for the volume of a cone.
{{{ V = (1/3)(pi)r^2*h}}}
You are told that Cone B has dimensions that are scaled to 9 times the dimensions of cone A.
So, the radius on cone B is 9r and the height on cone B is 9h.
Thus the volume for cone B is
{{{V[b] = (1/3)*(pi)*(9r)^2 *9h}}}
{{{V[b] = (1/3)(pi)r^2*h *9^3}}}
You are told Cone A has a volume of 10cm3.
You can also see that Cone B's volume is just {{{9^3}}} times that of Cone A.
So the volume of Cone B = 10*9^3 cm3