Question 196885
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if

*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y(t) = -\frac{1}{2}gt^2 + v_1t]


and


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x(t) = v_2t]


Then


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ t = \frac{x}{v_2}]


and


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y(x) = -\frac{1}{2}g\left(\frac{x}{v_2}\right)^ 2+ v_1\left(\frac{x}{v_2}\right)]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y(x) = -\frac{g}{2(v_2)^2}x^2 + \left(\frac{v_1}{v_2}\right)x]


Just plug in the given values and solve the resulting quadratic when *[tex \LARGE y(x) = 0]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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