Question 197330


From {{{-2x^2+5x-6}}} we can see that {{{a=-2}}}, {{{b=5}}}, and {{{c=-6}}}



{{{D=b^2-4ac}}} Start with the discriminant formula.



{{{D=(5)^2-4(-2)(-6)}}} Plug in {{{a=-2}}}, {{{b=5}}}, and {{{c=-6}}}



{{{D=25-4(-2)(-6)}}} Square {{{5}}} to get {{{25}}}



{{{D=25-48}}} Multiply {{{4(-2)(-6)}}} to get {{{(-8)(-6)=48}}}



{{{D=-23}}} Subtract {{{48}}} from {{{25}}} to get {{{-23}}}



Since the discriminant is less than zero, this means that there are two complex solutions.



In other words, there are no real solutions.