Question 197335
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{{{y-y[1]=m(x-x[1])}}}

{{{m=2/3}}}, {{{x[1]=2}}}, {{{y[1]=2}}}

{{{y-2=(2/3)(x-2)}}}

Multiply through by 3:

{{{3(y-2)=3(2/3)(x-2)}}}

Cancel the 3's on the right:

{{{3(y-2)=cross(3)(2/cross(3))(x-2)}}} 

{{{3(y-2)=2(x-2)}}}

Distribute:

{{{3y-6=2x-4)}}}

Add 6 to both sides:

{{{3y=2x+2}}}

Now you can go two ways from here.

1. Standard form:

{{{3y=2x+2}}}

Add -2x to both sides:

{{{-2x+3y=2}}}

Multiply by -1 so first term will be positive:

{{{2x-3y=-2}}}

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OR

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2. Slope-intercept form:

{{{3y=2x+2}}}

Divide through by 3

{{{y=2/3}}}{{{x+2/3}}}

Edwin</pre>