Question 197291
# 1

*[Tex \LARGE (3)^{\frac{1}{2}}+2i=\sqrt{3}+2i]


# 2

*[Tex \LARGE (16)^{\frac{1}{4}}+6=\sqrt[4]{16}+6=\sqrt[4]{2^4}+6=2+6=8]


So *[Tex \LARGE (16)^{\frac{1}{4}}+6=8]


# 3

*[Tex \LARGE 3-(-9)^{\frac{1}{2}}=3-\sqrt{-9}=3-3i]



So *[Tex \LARGE 3-(-9)^{\frac{1}{2}}=3-3i]



Note: *[Tex \LARGE i=\sqrt{-1}]