Question 197212
{{{(u^2-9)/(u-3)^2}}}={{{((u-3)*(u+3))/(u-3)(u-3)}}}={{{(u+3)/(u-3)}}}

Multiply: Fractions
{{{(((a-4)(a+3))/(a^2 - 4a))*(2a/(a+3)(a-1))}}}
={{{((a-4)(a+3)/a*(a-4))*(2a/((a+3)*(a-1)))}}}
={{{((a+3)/(a))*(2a/((a+3)*(a-1)))}}}
={{{(1/a)*(2a/(a-1))}}}
={{{2/(a-1)}}}

OK