Question 197102
h^2+29h-26=0
{{{h = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
h=(-29+-sqrt[29^2-4*1*-26])/2*1
h=(-29+-sqrt[841+104])/2
h=(-29+-sqrt945)/2
h=(-29+-30.74)/2
h=(-29+30.74)/2
h=1.74/2
h=.87 or .9 when rounded to the nearest tenth.
h=(-29-30.74)/2
h=-50.74/2
h=-25.37 or -25.4 when rounded.