Question 27139
{{{sqrt(32) / sqrt(25)}}} =
{{{sqrt(2*16)/5}}} =
{{{(sqrt(2) * 4) / 5}}}
next 
{{{sqrt(32)/2 * sqrt(2)}}} =
{{{sqrt(2*16)/2 * sqrt(2)}}} =
{{{((sqrt(2) * 4)/2) * sqrt(2)}}} 
notice that {{{sqrt(2) * sqrt(2) = 2}}}
{{{((2 * 4)/2) }}} = 4