Question 197152
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What you have is the difference of two squares.  *[tex \LARGE 256 = 16^2] and *[tex \LARGE 16t^2 = (4t)^2].


The factorization of the difference of two squares is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a^2 - b^2 = (a - b)(a + b)]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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