Question 27152
Remember that {{{X^(-1)}}} = {{{1/x}}} and vice-versa.

So now re-arranging the given problem, keepin in mind the above statement

{{{(6y^3y^2/xx^2)*(1/xy^2(4x^2y)^2)}}}
Adding the exponents for the common terms
{{{(6y^5/x^3)*(1/xy^2(16(x^4)(y^2)))}}}
Can you solve it from here??