Question 27188
Let the first integer be x
Let the second integer be y
x+y=29 Solve for y
y=29-x (subsitution)


3x=3+4y
Subsitute for y
3x=3+4(29-x)
3x=3+116-4x
7x=119
x=17


y=29-17
y=12


Hence, the two integers are 17 and 12.
Paul.