Question 196962
{{{8x=(y^2-6y+9)-9-3}}}
:
{{{8x+12=(y-3)^2}}}
:
{{{x+3/2=(1/8)(y-3)^2}}}
:
vertex is at (-3/2,3)
:
{{{1/4p=1/8}}}
:
{{{4p=8}}}--->p=2
:
we know this opens to the right
:
directrix is at x=-7/2
:
focus is at (1/2,3)