Question 196646
 for RHS factoring out log(base2) we have
 log(base2)[6x] since loga+logb=log(ab)
 equating LHS and RHS we have
 log(base2)[x^2+8]=log(base2)[6x]
 cancelling log(base2)since it is commom on both sides
 x^2+8=6x
 x^2-6x+8=0 a quadratic equation
 solving for x we get 
 x=4or2