Question 196991

{{{(3a+4)(4a-3)}}} Start with the given expression.



Now let's FOIL the expression.



Remember, when you FOIL an expression, you follow this procedure:



{{{(highlight(3a)+4)(highlight(4a)-3)}}} Multiply the <font color="red">F</font>irst terms:{{{(3a)(4a)=12a^2}}}.



{{{(highlight(3a)+4)(4a+highlight(-3))}}} Multiply the <font color="red">O</font>uter terms:{{{(3a)(-3)=-9a}}}.



{{{(3a+highlight(4))(highlight(4a)-3)}}} Multiply the <font color="red">I</font>nner terms:{{{(4)(4a)=16a}}}.



{{{(3a+highlight(4))(4a+highlight(-3))}}} Multiply the <font color="red">L</font>ast terms:{{{(4)(-3)=-12}}}.



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So we have the terms: {{{12a^2}}}, {{{-9a}}}, {{{16a}}}, and {{{-12}}} 



{{{12a^2-9a+16a-12}}} Now add every term listed above to make a single expression.



{{{12a^2+7a-12}}} Now combine like terms.



So {{{(3a+4)(4a-3)}}} FOILs to {{{12a^2+7a-12}}}.



In other words, {{{(3a+4)(4a-3)=12a^2+7a-12}}}.