Question 196966
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Let <b><i>n</i></b> represent the number of nickels


Let <b><i>d</i></b> represent the number of dimes


Let <b><i>q</i></b> represent the number of quarters


There are 5 more dimes than quarters:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ d = q + 5 \ \ \Rightarrow\ \ q = d - 5]


There are twice as many nickels as dimes:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ n = 2d]


The total amount of money is given as $3.25, but the problem will be simpler to express if you convert this amount to 325 cents.


The value of each nickel is 5 cents, so the total value of nickels is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 5n = 10d]


The value of each dime is 10 cents, so the total value of dimes is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 10d]


And the value of each quarter is 25 cents, so the total value of quarters is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 25q = 25(d - 5)]


Since we now have three expressions of value all involving the number of dimes, we can add them together and know that the sum is the same as the total amount of money:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 10d + 10d + 25(d - 5) = 325]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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