Question 196131
There is a right angle triangle with hypotenuse 1320'.
a^2+b^2=c^2
a=b+55
(b+55)^2+b^2=1320^2
b^2+110b+3025+b^2=1742400
2b^2+110b-1739375=0
b=905'
a=960'
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Ed
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*[invoke quadratic "x", 2, 110, -1739375]