Question 196886
sol:
let the width be x
twice the width=2x
length=5 less than the twice the width
length=2x-5
perimeter of the rectangle=2*(length+width)
                          =2*(2x-5+x)
                          =2*(3x-5)
                          =2*3x-2*5
                          =6x-10
according to the problem perimeter=50 cm
           6x-10=50
adding 10 on both sides
6x-10+10=50+10
6x=60
dividing by 6 on both sides
6x/6=60/6
x=10
width=10 cm
length=2x-5
      =2*10-5
      =20-5
      =15 cm

length=15cm,width=10cm