Question 196826


{{{4x+8y=12}}} Start with the given equation.



{{{8y=12-4x}}} Subtract {{{4x}}} from both sides.



{{{8y=-4x+12}}} Rearrange the terms.



{{{y=(-4x+12)/(8)}}} Divide both sides by {{{8}}} to isolate y.



{{{y=((-4)/(8))x+(12)/(8)}}} Break up the fraction.



{{{y=-(1/2)x+3/2}}} Reduce.



So the equation {{{y=-(1/2)x+3/2}}} is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=-1/2}}} and the y-intercept is {{{b=3/2}}} 


note: the y-intercept is the point *[Tex \LARGE \left(0,\frac{3}{2}\right)]