Question 196798
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Let <b><i>x</i></b> represent the width of the rectangle.  Then the length of the rectangle must be <b>2<i>x</i> + 3</b>.  Since the area of a rectangle is length times width:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x(2x + 3) = 90]


so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x^2 + 3x - 90 = 0]


Solve the quadratic. Hint: It factors rather tidily.  Exclude the negative root because you are looking for a positive measure of length.  The positive root will give you the width and the length follows from the given relationship between length and width.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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