Question 196790
<pre><font size = 4 color = "indigo"><b>
{{{(3/4)t - (7/12)= (1/6)}}}

The LCD of the denominators 4, 12, and 6
is 12.  So we multiply every term on both 
sides by 12, written as {{{12/1}}} 

{{{(12/1)(3/4)t - (12/1)(7/12)= (12/1)(1/6)}}}

All the denominators cancel out:

{{{(""^3cross(12)/1)(3/cross(4))t - (""^1cross(12)/1)(7/cross(12))= (""^2cross(12)/1)(1/cross(6))}}}

All that's left is

{{{9t-7=2}}}

You can solve that and you'll get {{{t=1}}}

Edwin</pre>