Question 196774
x^6 -9x^3 +8 =0
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let  y=x^3
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y^2 -9y +8 =0
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(y-8)(y-1) =0
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y=8,,1
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but,,,y=x^3
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x^3 =8
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x=2
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x^3 =1
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x=1
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