Question 196768
this  technique  is  called  grouping
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x^3 +3x^2 +3x +9
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x^2 ( x+3) +   3 (x+3)
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(x^2 +3)  * (x+3),,,,,,sometimes  hard  to  see  this  step,  like  ab +cb = b(a +c)
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(x^2 +3) (x+3)
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checks  with  x=1,  original  =  answer = 16
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IF  problem  really  does  have  a  "-9",  check  for  another  (-) sign
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if  not  ,  X^3 +3(x^2 +x -3)
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Use  quadratic  eqn
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x^3 +3 ( x-1.3) (x+2.3)
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