<PRE><B>Question 196718</B>
A  rough  sketch  helps,,,label  as  answer  arise
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ADE  is  a  rt  triangle,,with  AE = 5,,,DE  =13,,,given
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using  pythagorous  theorem,,c^2 = a^2 +b^2.
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13 ^2 = 5^2 + ad^2,,,,ad  =  12 ,,,,,,,(a)
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CB  =AD =12,,,,,,and  DC=AB =20,,,,,given,,, therefore  BE =15  (Ab - AE = BE)
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Per  EBCD = 15 +12 +20+13 = 60,,,,,, (b)
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Area  (AED)  = 1/2 * 5 * 12  =  30,,,,,,(c)
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Area  (ABCD) = 20 *12  +240,,,,,(d)
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Area(EBCD) = 1/2 *(15 +20) *12  =  210
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