Question 196701
Solve using the quadratic formula: 
4x squared+4x=15 
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{{{4x^2 + 4x - 15 = 0}}}
(2x-3)*(2x+5) = 0
x = 3/2
x = -5/2
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Using quadratic formula:
*[invoke solve_quadratic_equation 4,4,-15]