Question 196658
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For problem one, enter 2x^2 - 7x - 15 and click Factor. Once you have the terms, set each term =0 and solve
{{{2x^2 - 7x - 15}}}
{{{(2x +3)(x-5)}}}
2x+3 = 0 ==> x = -3/2
x-5 = 0  ==> x = 5

for 2) put it in the form (5x + 2)^2 - 9 and then click factor. The solve as above
3)x^2  - 12x + 32, then click factor. solve as above
4)
{{{x/(x - 1) = (x + 5)/x}}}
{{{x^2 = (x-1)(x+5)}}}
{{{x^2 = x^2 + 4x - 5}}}
{{{0 = 4x-5}}}
{{{x = 5/4}}}