Question 196653
{{{(-2x^(-2))^2}}} Start with the given expression.



{{{((-2)^1*x^(-2))^2}}} Rewrite {{{-2}}} as {{{(-2)^1}}}



{{{(-2)^(1*2)*x^(-2*2)}}} Multiply the outer exponent with every exponent inside the parenthesis.



{{{(-2)^2*x^(-4)}}} Multiply



{{{4*x^(-4)}}} Square -2 to get 4



{{{4/x^4}}} Flip the fraction to make the exponent positive.



So {{{(-2x^(-2))^2=4/x^4}}} where {{{x<>0}}}