Question 27097
LEt the three integers be x, x+2 and x+4


{{{(x+4)^2=76+(x+2)^2}}}
{{{x^2+8x+16=76+x^2+4x+4}}}
{{{x^2-x^2+8x-4x=76+4-16}}}
{{{4x=64}}}
x=16


16+2=18
16+4=20
Hence, the three consecutive integers are 16, 18 and 20.
Paul.