Question 196532
Solve for x:
{{{4x^2-8x+7 = 0}}} using the quadratic formula:{{{x = (-b+-sqrt(b^2-4ac))/2a}}}
{{{x = (-(-8)+-sqrt((-8)^2-4(4)(7)))/2(4)}}}
{{{x = (8+-sqrt(64-112))/8}}}
{{{x = (8+-sqrt(-48))/8}}}
{{{x = (8+-sqrt(-3*16))/8}}}
{{{x = (8/8)+(4/8)(sqrt(-3))}}}or{{{x = (8/8)-(4/8)(sqrt(-3))}}} Simplifying:
{{{x = 1+(sqrt(3)/2)i}}} or {{{x = 1-(sqrt(3)/2)i}}}