Question 196328
{{{1000000=420000(1+.065/52)^(52(t))}}}
:
{{{2.38=(1.00125)^(52(t))}}}
:
log2.38 =.376759395
:
log {{{1.00125^52t}}}=52tlog(1.00125)
:
.3768=52t(.00054)
:
.3768=.02808t
:
t=13.42 years