<PRE><B>Question 196272</B>
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Let &lt;b&gt;&lt;i&gt;x&lt;/i&gt;&lt;/b&gt; represent the amount of 30% solution, then &lt;b&gt;200- &lt;i&gt;x&lt;/i&gt;&lt;/b&gt; is the amount of 50% solution.


So &lt;b&gt;.3&lt;i&gt;x&lt;/i&gt;&lt;/b&gt; is the amount of pure insecticide in the 30% solution, &lt;b&gt;.5(200- &lt;i&gt;x&lt;/i&gt;)&lt;/b&gt; is the amount pure insecticide in the 50% solution, and &lt;b&gt;.42(200)&lt;i&gt;&lt;/i&gt;&lt;/b&gt; is the amount of pure insecticide in the mixture, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ .3x + .5(200 - x) = .42(200)]


Solve for &lt;b&gt;&lt;i&gt;x&lt;/i&gt;&lt;/b&gt;


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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