Question 3387
To solve this problem, start with the smallest and call it n. The next three numbers are n+1 and n+2, so the sum of these numbers is:<br>
n +(n+1) + (n+2) = 126.<br>
This equation reduces to:<br>
3n+3 = 126 subtracting 3 from either side makes it<br>
3n = 123 and dividing either side by 3 means<br>
n = 41<br>

The smallest is 41 so the largest is 43