Question 196159
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Given Line Eqn, {{{ y=(-7/3)x+1/5}}} has a {{{Slope=m=-7/3}}}.


*Remember for perpendicular lines, the Slope of other is reverse reciprocal:
{{{m[2]=-1/m=-1/(-7/3)=(-1)(-3/7)}}}
{{{red(m[2]=3/7)}}}



Then thru point (7,15) with {{{slope=m[2]=3/7}}}:
{{{y=mx+b}}}
{{{15=(3/cross(7)1)(cross(7)1)+b}}}
{{{b=15-3=12}}}, Y-Intercept


It follows line eqn---> {{{green(y=(3/7)x+12)}}} in SLope-Intercept Form passing thru point (7,15).


{{{drawing(400,400,-20,20,-15,20,grid(1),graph(400,400,-20,20,-15,20,(-7/3)x+1/5,(3/7)x+12),blue(circle(7,15,.30)),green(locate(1.2,12,Yintercept)),blue(circle(0,12,.25)),green(circle(0,12,.18)))}}} ----> {{{red(y=(-7/3)x+1/5)}}}; {{{green(y=(3/7)x+12)}}}


Thank you,
Jojo</font>