Question 196111
sol:
a-3[b-5(c-x)]=2
first take L.H.S part
a-3[b-5(c-x)]
a-3[b-(5c-5x)]
a-3[b-5c+5x]     (i.; -*-=+)
a-3b+15c-15x
a-3b+15c-15x=2
-15x=2-a+3b-15c
15x= -2+a-3b+15c
x=(-2+a-3b+15c)/15