Question 196072
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1. graph the line that passes through(-2,-3) and has a slope -1/2. 


Via Slope-Intercept Form:
{{{y=mx+b}}}
{{{-3=(-1/cross(2)1)(cross(-2)-1)+b}}} ---> {{{-3=(-1)(-1)+b}}}
{{{-3=1+b}}}
{{{b=-3-1=red(-4)}}}, Y-Intercept


It follows ----> {{{red(y=(-1/2)x-4)}}} or 
In Std.Form, {{{(1/2)x+y=-4}}}, multiply by 2
{{{red(x+2y=-8)}}}


Let Fy=0
{{{x+2(0)=-8}}}
{{{red(x=-8)}}}, X-Intercept
{{{drawing(350,350,-10,10,-10,10,grid(1),graph(350,350,-10,10,-10,10,(-1/2)x-4),blue(circle(-8,0,.15)),blue(circle(0,-4,.15)),green(circle(-2,-3,.15)))}}}


2. graph 2x-3y=-3


Let Fy=0
{{{2x-3(0)=-3}}}--->{{{cross(2)x/cross(2)=-3/2}}}
{{{red(x=-3/2)}}}, X-Interecpt (-3/2,0) or (-1.5,0)


Let Fx=0
{{{2(0)-3y=-3}}} ---> {{{cross(-3)y/cross(-3)=cross(-3)1/cross(-3)1}}}
{{{red(y=1)}}}


{{{drawing(300,300,-5,5,-5,5,graph(300,300,-5,5,-5,5,(2x+3)/3),blue(circle(-1.5,0,.10)),blue(circle(0,1,.10)),green(arrow(1,1.5,2,1)),green(locate(2,.7,2x-3y=-3)))}}}


Thank you,
Jojo</font>