Question 195927
    Three consecutive even integers are such that the square of the third is 100 more than the square of the second. Find the three integers.
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Let x = first consecutive even integer
then
x+2 = second consecutive even integer
x+4 = third consecutive even integer
.
(x+4)^2 = (x+2)^2 + 100
(x+4)(x+4) = (x+2)(x+2) + 100
x^2+8x+16 = x^2+4x+4 + 100
x^2+8x+16 = x^2+4x+104
8x+16 = 4x+104
4x+16 = 104
4x = 88
x = 22 
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The three integers: 22, 24, 26