Question 195949
The sum of the squares of three consecutive, positive integers is equal to the sum of the squares of the next two integers. Find the five integers. 

x + x +2 + x + 3 = x squared + x squared.. is the best I can come up with???? help! Thanks.
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It's 3 consecutive integers:
x^2
(x+1)^2
(x+2)^2

= 3x^2 6x + 5
That's equal to (x+3)^2 + (x+4)^2
3x^2+6x+5 = x^2+6x+9 + x^2+8x+16
3x^2+6x+5 = 2x^2 + 14x + 25
x^2 - 8x - 20 = 0
(x-10)*(x+2) = 0
x = 10 (-2 is not positive)
100 + 121 + 144 =? 169 + 196
365 = 365
x = 10 works