Question 195833
{{{c[n]=(-3/2)^(n-3)}}}
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Let's find the first two terms:

Let n=1

{{{c[1]=(-3/2)^(1-3)=(-3/2)^(-2)=(-2/3)^2=4/9}}}

{{{c[2]=(-3/2)^(2-3)=(-3/2)^(-1)=(-2/3)^1=-2/3}}}


The common ratio is found by dividing any term by
the preceding term, so we'll divide {{{c[2]/c[1]=(-2/3)/(4/9)=(-2/3)(9/4)=-3/2}}}

So the ommon ratio {{{r=-3/2}}}

The 10th term is

{{{c[10]=(-3/2)^(10-3)=(-3/2)^(7)=-2187/128}}}

Edwin</pre>