Question 195796
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Write an equation in slope-intercept form of a line containing the point (8,-12) and (6,4).


Getting the Slope via Point-Slope form:
{{{m=(y[2]-y[1])/(x[2]-x[1])=(4-(-12))/(6-8)=(4+12)/-2=16/-2}}}
{{{red(m=-8)}}}


Thru point (8,-12):
{{{y=mx+b}}}
{{{-12=(-8)(8)+b}}}
{{{b=-12+64=red(52)}}}, Y-Intercept


Also, thru point (6,4):
{{{4=(-8)(6)+b}}}
{{{b=4+48=red(52)}}}


Therefore, it follows ---> <font color=blue>y = -8x + 52</font>, Answer
{{{drawing(400,400,-10,10,-18,70,grid(1),graph(400,400,-10,10,-18,70,-8x+52),blue(circle(8,-12,.15)),blue(circle(6,4,.15)),green(circle(0,52,.15)),green(locate(1,53,Y-intercept)))}}}



Thank you,
Jojo</font>