Question 195797
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Write an equation in slope-intercept form of a line containing the point (10,-12) and (13,18).



First, we get the Slope via Point-Slope Form:
{{{m=(y[2]-y[1])/(x[2]-x[1])=(18-(-12))/(13-10)=(18+12)/3=30/3}}}
{{{red(m=10)}}}



Then, thru point (10,-12) in Slope-Intercept Form:
{{{y=mx+b}}}
{{{-12=10(10)+b}}} ---> {{{12=100+b}}}
{{{b=-12-100=red(-112)}}}, Y-Intercept


Also, thru point (13,18): (should be the same)
{{{18=10(13)+b}}}
{{{18=130+b}}}
{{{b=18-130=red(-112)}}}


Therefore, it follows, <font color=blue>y = 10x - 112</font>, Answer


{{{drawing(400,400,-10,20,-140,70,grid(1),graph(400,400,-10,20,-140,70,10x-112),blue(circle(13,18,.25)),blue(circle(10,-12,.25)),blue(circle(0,-112,.25)),green(locate(2,-115,Yintercept)))}}}


Thank you,
Jojo</font>