Question 195769
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Let us re-state the following dimensions:


One leg (a) = <font color=blue>x cm</font>
Longer leg (b) = <font color=blue>x + 7 cm</font> 
Hypotenuse (c) = <font color=blue>x + 7 + 2 = x + 9 </font>


By Pyth.theorem:
{{{a^2+b^2=c^2}}}
{{{x^2+(x+7)^2=(x+9)^2}}}
{{{x^2+x^2+14x+49=x^2+18x+81}}}
{{{x^2+cross(x^2)+14x+49-cross(x^2)-18x-81=0}}}
{{{x^2-4x-32=0}}}
{{{(x-8)(x+4)=0}}}
{{{x=-4}}}, disregard "-"
{{{red(x=8cm)}}}, One leg


Longer leg, {{{x+7=8+7=red(15cm)}}}


Hypotenuse: {{{x+9=8+9=red(17cm)}}}


Check,(Pyth.Theorem)
{{{8^2+15^2=17^2}}}
{{{64+225=289}}}
{{{289=289}}}


Thank you,
Jojo</font>