Question 195769
Find the length of the hypotenuse of a right angled triangle with one leg 7 cm longer than the other and the hypotenuse 2 cm longer than the longer leg. So the hypotenuse = x+9, one side = x and the other side = x+7. I'm not sure what to do next 
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Solve (x+9)^2 = x^2 + (x+7)^2 for "x".
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Cheers,
Stan H.